Log in to add a comment

## Answers

OPD = k (2d1 -2d2)

where d1,2 are arms 1 and 2 of the interferometer and k is the wavenumber of the light used. If one mirror is moved a distance, the number of fringes that will cross the field of view is given by

k (2Δd) = (2π/λ) (2Δd) = (2π) m

λ = 2Δd / m = 2*0.223E-3 / 769

λ = 579 nm

Hope this helps:)