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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let us consider the points as A(0,0) ; B(3,4) ; C(0,8) ; D(-3,4) The distance b/w AB = √(3-0)²+(4-0)² = √25 = 5 The distance b/w BC = √(0-3)²+(8-4)² = √9+16 = 5 The distance b/w CD = √(-3-0)²+(4-8)² = √9+16 = 5 The distance b/w DA = √(-3-0)²+(4-0)² = √25 = 5 The distance b/w AC =√(0-0)²+(8-0)² = 8 The distance b/w BD = √(-3-3)²+(4-4)² = 6 As the distance of all sides are equal and diagonals are not equal. Therefore the given points represents Rhombus

Indirectly U r asking to prove that this points represent a rhombus or not As we all know that rhombus has all its sides equal.So lets name the points as A(0,0),B(3,4),C(0,8),D(-3,4) By taking out the difference from this points, we get, AB=(0-3)+(0-4)=1 BC=(0-3)+(8-4)=1 CD=(-3-0)+(4-8)=1 AD=(-3-0)+(4-0)=1 we can see AB=CD=BC=AD This mean that the points are the edges of a rhombus.

you have shown only all sides are equal.we can't decide whether the given points form a rhombus.Becuase all sides equal fo both rhombus and square.If want to whether it is a square or rhombus you need find distance between AC and BD.If you get AC=BD it is a square. If you get AC ≠D it is a rhombus.