# A 100 g mass moving at 6 m/s collides with another 100 g mass at rest, find the velocity of second mass after the collision ,if the first comes to rest.

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by nausheensana

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by nausheensana

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Mass of object 1, **m1**= 100 g

initial velocity of object 1,**u1**= 6 m/s

final velocity of object 1,**v1**= 0 m/s

mass of object 2,**m2**= 100 g

initial velocity of object 2,**u2**= 0 m/s

final velocity of object 2,**v2**= ?

From the law of conservation of momentum, we have

**total initial momentum = total final momentum**

m1u1 + m2u2 = m1v1 + m2v2

⇒ 100 g × 6 m/s + 100 g × 0 m/s = 100 g × 0 m/s + 100 g × v2

⇒ 600 gm/s + 0 gm/s = 0 gm/s + 100g × v2

⇒ 600 gm/s = 100g ×v2

⇒ 6 m/s = v2

⇒ v2 = 6m/s

Therefore, the velocity of second mass after the collision is **6 m/s **.

initial velocity of object 1,

final velocity of object 1,

mass of object 2,

initial velocity of object 2,

final velocity of object 2,

From the law of conservation of momentum, we have

m1u1 + m2u2 = m1v1 + m2v2

⇒ 100 g × 6 m/s + 100 g × 0 m/s = 100 g × 0 m/s + 100 g × v2

⇒ 600 gm/s + 0 gm/s = 0 gm/s + 100g × v2

⇒ 600 gm/s = 100g ×v2

⇒ 6 m/s = v2

⇒ v2 = 6m/s