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A train when moves at an speed of 40kmph reaches its destination on time when its avge speed becomes 35 kmph then it reaches its destination 15 minuites

late find the length of journey?


Total distance travelled =x
then when the train is travelling with the velocity,v=40
and when the tym has been delayed 15 min.,then the  velocity will be,
=>40t=35t+525[frm eq.1]
sub.t in eq.1,
require distance=4200km
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Just say that it takes time="t" hrs  to reach its destination while moving at an avg speed of 40kmph. therefore distance= 40t. now, 15 min = 1/4 hr. therefore you get distance= 35(t+1/4) = 35t + 35/4. hence 40t = 35t+35/4 => 5t = 35/4 => t = 7/4 hrs. so distance = 40t = 40*7/4 = 70 km.
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