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Given:-ABCD is a trapezium, AB II DC To Prove:- AO/BO = CO/DO or by alterando AO/CO = BO/DO Construction:-EF II DC Proof:- In ▲ACD , OE II CD AE/ED = AO/OC (By BPT)......(1) In ▲ABD , DC II EF II AB OR EF II AB AE/ED = BO/DO (By BPT)........(2) By (1) and (2), we get AO/CO = BO/DO Hence proved
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