Answers

2015-08-27T18:41:51+05:30


sina = root of cos^2a

so seca=1/cosa

seca= 1/root of(sin^2-1)

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2015-08-29T19:28:32+05:30
As cosA is = 1/secA and (cosA) sq + (sinA ) sq = 1 put value of cosA in this and shift 1/secA sq to left side then it will come in terms of sinA like sinA sq = 1-(1/secA sq ) and take LCM of left side (secA sq -1)/ secA sq
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