Answers

2015-08-30T21:45:47+05:30
Let the charge = Q
given that F/Q = 2.0 N/C

F=9 \times 10^9 \times  \frac{Q^2}{d^2} \\ \\ \frac{F}{Q} =9 \times 10^9 \times  \frac{Q}{d^2} \\ \\2=9 \times 10^9 \times  \frac{Q}{0.5^2} \\ \\ Q =  \frac{2 \times 0.5^5}{9 \times 10^9}=5.55 \times 10^{-11}\ C
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