Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions


This is an equation of a parabola of the standard form: (y-k)^2=4p(x-h), (h,k) being the (x,y) coordinates of the vertex. Parabola opens rightwards.
For given equation:
vertex: (-3,2)
Focus=(-3+p,2)=(-3+1,2)=(-2,2) (p units from vertex on axis of symmetry)
Axis of symmetry: y=2 (a horizontal line thru the vertex)
Directrix: x=-4 (a vertical line p units from vertex on axis of symmetry)
0 0 0
The Brainliest Answer!
Y^2=4y - 4x 
=>(y+2)²=4(x-1) which is the form of Y²=4aX
where X=x-1 and Y=y-2 and 4a=4,therefore a=1
For the vertex,
X=0,Y=0 i.e.,x+1=0,or x=1 and y-2=0,or y=2
Therefore coordinates of vertex are (1,2)
1 5 1
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts