Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Let the first stone be dropped at time t = 0. then the second stone is dropped at time t = 1 sec.

initial velocity for both stones = 0 m/s acceleration = g.

The distance travelled by the first stone in time t sec = s1 = u t + 1/2 a t² s1 = g t² /2 distance travelled by the second stone in time duration (t -1) sec. s2 = g (t -1)² /2

the separation between them : s1 - s2 = g/2 * [t² - (t-1)²] = g (t - 1/2)

This can also be found using the formula for distance travelled by a particle with uniform acceleration a during the nth second: S_n = (n - 1/2) a

calculations: distance of separation = 10 * (1 - 1/2) = 5 meters at 2:30:31 pm distance of separation = 10 * (5 - 1/2) = 45 meters at 2:30:35 pm