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The perimeter of an isosceles triangle is 42 cm and its base is (3/2) times each of equal sides. find the length of each side of the triangle, area of the

Let the side of the isosceles triangle be x GIVEN 3/2 x +x +x=42cm 3x/2 + 2x =42 (3x+4x)/2=42 3x+4x=84 7x=84 x=12cm side=12cm base=18cm The height(altitude) of an isos. trangle divides it into two rt trangles in a rt.trangle, base²+heigrt²=hypotenuse² thus, 9²+h²=12² h=√12²-9² =√144-81 =√63 =3√7cm area =1/2 x base x hieght =1/2 x 18 x3√7 27√7cm²