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1-sin²Ф/sinФ=L thus cotФcosФ=L
1-cos²Ф/cosФ=m thus tanФcosФ=m
l²m²(l²+m²+3)=(cotФcosФtanФcosФ)²(cot²Фcos²Ф +tan²Фcos²Ф +3)

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