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Two forces of magnitude 12 N and 8 N are acting at a point. If

the angle between the two forces is 60°, determine the magnitude
of the resultant force?


I think the answer is 7.57567675  do  like this   144 +64 = 208 do the square root of the answer and multiply it with sin30

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Given forces are 12N and 8N and angle b/w them is Ф=60°
therefore by parallelogram addition law
resultant, R= \sqrt{ 12^{2}+ 8^{2} +2*12*8*cos60 }  \\ \sqrt{304}  \\ 17.435 (approx)
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