Find rational numbers 'a' and 'b' so that

1) 7+√7/ 7-√5 - 7-√√5/ 7+√5 = a + 7/11 √5 b

2) 5+√5/ 7+4√3 = a - b√3

Simplify

1) (64/25) power -3/2

2) (81/49) power 3/2

3) {5 [8 power 1/3 + 27 power 1/3] power 3} power 1/4

Prove that

[5 power a/5 power b] whole power a+b × [5 power b/5 power c] whole power b+c × [5 power c/5 power a] whole power c+a = 1
URGENT!!!! ABSOLUTELY URGENT!!! MORE THAN URGENT!!!!

1
I did. He had messaged me in fear of moderators deleting his answer as he can answer only the simplify one
But I told him not to worry. I said I'll talk to them
Except simplify please do others!! D;
its done i dont know about rational numbers
thanks yasmin

Answers

The Brainliest Answer!
  • Brainly User
2014-06-12T22:48:46+05:30
SIMPLIFY:
1)(64/25) power -3/2
={(2)power 6/(5)power 2}power -3/2
=2 power 6*-3/2 /5 power 2*-3/2
=2 power -9/5 power -3
=5 power 3/2 power 9=125/512=4.096

2)(81/49) power 3/2
={(9) power 2/(7) power 2}power 3/2
=(9/7) power 2*3/2
=(9/7) power 3=729/343

3){5[8 power 1/3+27 power 1/3]power 3}power 1/4
={5[2 power 3*1/3+3 power 3*1/3]power 3}power 1/4
={5[2+3]power 3}power 1/4
={5*5 cube}1/4
=5 power 4*1/4
=5 

4)the same question
=(5 power a-b)power a+b*(5power b-c)power b+c*(5 power c-a)power c+a
=5 power a(a+b)-b(a+b)*5 power b(b+c)-c(b+c)*5 power c(c+a)-a(c+a)
=5 power a2+ab-ab-b2+b2+bc-bc-c2+c2+ac-ac-a2
Since all numbers get cancelled 
=5 power 0=1[hence proved]
Finally Yasmin sorry for being late i have completed it was a tedious task. 

THANK YOU &GOOD NIGHT 
:) :)
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