Answers

2015-09-06T11:40:54+05:30
Let Rehan's  present age = x
his son's present age = y

two years ago, 
rehan's age = x-2
his son's age = y-2
so x-2 = 3(y-2)
⇒ x = 3y - 6 + 2
⇒ x = 3y - 4

two years hence, 
rehan's age = x+2
his son's age = y+2
so 2(x+2) = 5(y+2)
⇒ 2x + 4 = 5y +10
⇒ 2(3y-4) = 5y + 10
⇒ 6y - 8 = 5y + 10
⇒ y = 18

x = 3*18 - 4 = 50

Sum of their ages = 50+18 = 68
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