Answers

2015-09-06T12:48:28+05:30
CosecФ-sinФ=L 1-sin²Ф/sinФ=L thus cotФcosФ=L secФ-cosФ=m 1-cos²Ф/cosФ=m thus tanФcosФ=m l²m²(l²+m²+3)=(cotФcosФtanФcosФ)²(cot²Фcos²Ф +tan²Фcos²Ф +3) =(cos²Ф)²(cos²Ф(cot²Ф+tan²Ф)+3) =1
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