Answers

  • lsv
  • Ambitious
2014-02-01T23:48:22+05:30
sum of natural Numbers from 1 to n is given by the formula, 
Sn = n(n + 1)/2 
in your case n = 100 
sum = 100(100 + 1)/2 = 50 × 101 = 5050 

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  • man
  • Ambitious
2014-02-02T00:10:45+05:30
For an A.P. given, formula for its sum is:
S  n=n/2 [a+l]
where a = first term of A.P. and l=last term of A.P.
Sn=100/2 [1+100]=50(101)=5050
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