Answers

2015-09-06T19:09:11+05:30
Mx²+nx+1⇒
sinθ+cosθ=-n/m
=msin²θ+nsinθ+1=0                 ---------- eqn 1
mcos²θ+n cosθ+1=0                    --------------- eqn 2
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On solving the equations we get:--
m +n(-n/m)+2=0
⇒m-n²/m+2=0
⇒m²-n²+2m=0
m²+2m=n²                        Ans.
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