Answers

2015-09-07T14:49:58+05:30
Let x=a^2-b^2
y=b^2-c^2
z=c^2-a^2
now,
x+y+z=a^2-b^2+b^2-c^2+c^2-a^2=0
we know that if x+y+z=0
so,x^3+y^3+z^3=3xyz
(From identity 10)
(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=3(a^2-b^2)(b^2-c^2)(c^2-a^2)=3(a+b)(b+c)(c+a)(a-b)(b-c)(c-a)


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