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A force is inclined to 50 degree to the horizontal. if its rectangular compound is horizontal direction be 50n find the magnitude of force and its vertical

component ...



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Let the force be F
it is inclined at 50 degree with horizontal.

So F cos50 = 50N
⇒ F = 50/cos50 N
⇒ F = 77.78 N

vertical component, F sin50 = 77.78×sin50 = 59.58 N
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