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A triangle ABC whose vertices A, B, C are (0, 0), (0, 2), (3, 0) nd find area of the triangle so formed

plzzz help me.....
is the answer 3....?????


Yes the answer is 3. by 1/2 *base *height, we get 3*2/2=3. 
your answer is right it is 3
0 0 0
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