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2015-09-11T21:25:29+05:30

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Genral pythagoras triplet is (m , m²+1 , m²-1)

∴m = 41

Genaral pythagoras triplet = (41 , 41²+1 ,41²-1)
    
                                      = (41 , 1681+1 , 1681-1)
 
                                      = (41 , 1682 , 1680)


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you forgot to divide....
by 2
sorry i forgot
2015-09-12T10:44:59+05:30
For a given odd number m, the pythagorean triplets are (m,\  \frac{m^2-1}{2},\ \frac{m^2+1}{2})


For a given even number m, the pythagorean triplets are (m,\  (\frac{m}{2})^2-1,\ (\frac{m}{2})^2+1)

here, m=41 (odd)
so triplets are: (41,\ \frac{41^2-1}{2},\ \frac{41^2+1}{2})

= (41, 840, 841)
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