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A force is inclined at 60˚ to the horizontal. if the horizontal component of the force is 40 kg wt,calculate the vertical component




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Force = F
\vec{F}\ is\ inclined\ to\ horizontal\ (x-axis)\ at\ 60^0\ deg.\\\\F_x=F\ Cos(\pi/3)=40\ kg\ wt\\\\F=\frac{40}{0.50}=80\ kg\ wt\\\\F_y=vertical\ component=F\ Sin(\pi/3)=40*\sqrt3\ kg \ wt.
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