Answers

  • JBM
  • Ambitious
2015-09-19T21:12:50+05:30
For having infinitely many solutions,
                                 a1/a2=b1/b2=c1/c2
∴k/2(k+1)=3/9=2k+1/7k+1
∴k/2(k+1)=1/3
2k+2=3k
∴k=2
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