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A rhombus has all four sides equal.
Therefore, the perimeter of a rhombus would be A=4s.
The diagonals intersect each other at the centre of the rhombus.
Therefore the side will be the hypotenuse of a triangle with the other two sides 16/2 and 30/2.
Apply Pythagorean Theorem.

P= 4\sqrt{(\frac{16}2)^2+(\frac{30}2)^2} \\ \\ P= 4\sqrt{(8^2+15^2)} \\ P= 4\sqrt{64+225} \\ P= 4\sqrt{289} \\ P= 4\sqrt{17^2} \\ P= 4*17 \\ P=68


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