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2015-10-25T18:12:13+05:30

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See the diagram. 
Initial position  A and final position B.

OC = (R - r) Sin α
OD = (R - r) Sin (α+ Ф)
CD = h = (R -r) 2 SinФ/2 Cos(α+Ф/2)

moment of inertia of the ball about diameter = 2/5 * m r²
v = r ω

we apply the law of conservation of energy.

m g h = 1/2 m v² + 1/2 I ω²
=> 2 g h =  r² ω² + 1/5 * r² ω²
     ω² = (5/3) g h / r²
     ω = √ [10 g (R - r) SinФ/2 Cos (α+Ф/2) / r²]

If  α = 0, then    ω = (1/r) * √ [ 5 g (R - r) SinФ ]

1 5 1
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