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Use the fact that the diagonals of a rhombus are perpendicular bisectors of each other: Draw AC 5.6 cm
 Find the perpendicular bisector of AB, by swinging those red arcs with your compass with the sharp point on A and B.
 Since BD is given = 6.5, half of that is 3.25. So draw BD so that it is 3.25 cm on the left of the midpoint of AC and 3.25 on the right side of the midpoint of AC.
 Then draw the sides AB, BC, CD, and DA
Hope it'd be useful. Pls choose it the best answer.
MASelvam IITian 
2 5 2
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