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Total solution = 60 L Alcohol in solution = 20 L Let x L alcohol must be added to produce 50% alcohol. Then alcohol in solution at last = (x + 20) L Total solution at last = (60 + x) L Now, Alcohol at last is equal to 50% of total solution. x + 20 = 50(60 + x)/100 ⇒ x + 20 = (60 + x)/2 ⇒ x + 20 = 30 + x/2 ⇒ x - x/2 = 30 - 20 ⇒ (2x - x)/2 = 10 ⇒ x/2 = 10 ⇒ x = 10 * 2 ⇒ x = 20

Therefore, 20L of alcohol must be added in 60L solution to get 50% alcohol in the solution.

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Let x L of alcohol be added so total alcohol =( 20 + x )L total solution =( 60 + x ) L to get 50 % (x + 20)/(x + 60) * 100 = 50 ⇒ x = 20 L