# Lines PQ and RS intersect each other at ooint o if angel POR: angle ROQ = 5:7 then find all the remaining angles

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by venaHanda376

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by venaHanda376

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so POR and ROQ lie on the same plane thus, POR+ROQ= 180 degrees.

therefore. 5x+7x=180

12x=180

x= 180/12

=15

=> 5x- 5*15 =75 and 7x-7*x=105

now, POS is also 105 degrees as ROQ and POS are interior alternate angles and SOQ is also 75 degrees as POR ans SOQ are interior alternate angle..

[if you have any more doubts,do ask me as this is my fav. concept of math]