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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let f(z) = az³+4z²+3z-4 zero of the polynomial (z-3) = 3 (since,z-3=0⇒z=3) So,replacing z by 3, f(3) = a(3)³+4(3)²+3(3)-4 ⇒f(3) = 27a+36+9-4 ⇒f(3) = 27a+41 Let g(z) = z³-4z+a zero of the polynomial (z-3) = 3 (since,z-3=0⇒z=3) So,replacing z by 3, g(3) = (3)³-4(3)+a ⇒g(3) = 27-12+a ⇒g(3) = 15+a Given that the two polynomials leaves same remainder when divided by z-3 So,g(3)=f(3) ⇒15+a = 27a+41 ⇒15-41 = 27a - a ⇒-26 = 26a ⇒a = -1.

A= -13/4 eh?? i used factor theorem where i took Z=3 and substituted in both and got the answer as 9a+29 and 3+a now i equated both and got a = -26/8 and atlast i cancelled i mean divided and got -3/4