# The base (unequal side)of an isosceles triangle is 4 cm and its perimeter is 20 cm find its area

1
by sumit4

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by sumit4

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b = 4cm

perimeter = 20cm

⇒ a + a + b = 20cm

⇒ 2a + 4 = 20

⇒ 2a = 20 - 4 = 16cm

⇒ a = 16/2 = 8cm

s = perimeter/2 = 20/2 = 10cm

Area is 4√15 cm².