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(tan Ф+2)(2tanФ+1)=5tanФ+sec²Ф
lhs=(tan Ф+2)(2tanФ+1)
= 2tan² Ф+tanФ+4tan Ф+2
 =5tan Ф+2tan² Ф+2

we know
sec² Ф- tan² Ф=1
tan² Ф=sec² Ф-1
2 tan² Ф=2(sec² Ф-1)
=2sec² Ф-2

lhs= 5 tanФ+2sec² Ф-2+2
=5 tanФ+2sec² Ф
1 5 1
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