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There are 100 employees in a room.

99% are managers.
How many managers must leave the room to bring down the percentage of managers to 98%?



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Of 100 employees 99 of them are managers. To bring the percent to 98 one manager must leave the room!
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99% of 100 employees are managers=100×99/100=99 managers.
98%=99 managers
Therefore,One employ should leave the room

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Thats wrong...if 1 manager leaves its 98 managers and 1 employee left so the percent wud be (98/99)×100 = 98.9 % and not exactly 98 percent. ...the correct answer is 50 managers should leave the room...so the percentage of managers would be (49/50)×100 = 98% exactly....So, the correct answer is 50 MANAGERS
urs answer is the best gsarora 7
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