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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

A body falling from a height of 10 m rebound from a hard floor, it loses 20% of its energy in impact. what is the height to which it rises after impact\

Height of the ball reached h1=10 metre Let the potential energy be PE=mgh1 .....................eqn 1 And for the rebound let the height be h2 Energy loss is 20% So the relation will be PE*20/100=mg(h1-h2) now substituting eqn 1 we will get ⇒mgh1*20/100=mg(h1-h2) ⇒h1*20/100=h1-h2 ⇒h2+h1*20/100=h1 ⇒h2=h1- (h1*20/100) ⇒h2=h1{1-(20/100)} ⇒h2=10(80/100) ⇒h2=800/100 ⇒h2 = 8 metres Assumption : There is no friction between the air particles and the body. Hence, the height reached after the impact is 8 metres. Plz mark as the best if u liked it !!