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A body falling from a height of 10 m rebound from a hard floor, it loses 20% of its energy in impact. what is the height to which it rises after impact\



Height of the ball reached h1=10 metre
Let the potential energy be PE=mgh1       .....................eqn 1
And for the rebound let the height be h2
Energy loss is 20%
So the relation will be 
now substituting eqn 1
we will get
⇒h2=h1- (h1*20/100)
⇒h2 = 8 metres
Assumption : There is no friction between the air particles and the body.
Hence, the height reached after the impact is 8 metres.
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