# A string tied on a roof can bear a maximum tension of 50kg wt the minimum acceleration that can be acquired by a man of 98kg to descend will be

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by goldie1

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by goldie1

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Let T be the Tension in the string.

let the acceleration of the descending man be a. It is the weight of the person which gives acceleration to the person. But tension opposes the weight.

m g - T = m a

T = m (g - a)

a = g - T/m

given the maximum tension T, so we get the minimum acceleration. So the person must descend with more acceleration than this.

a = g - 50 * g / 98 = 4.8 m/sec² if g = 9.8 m/s²

let the acceleration of the descending man be a. It is the weight of the person which gives acceleration to the person. But tension opposes the weight.

m g - T = m a

T = m (g - a)

a = g - T/m

given the maximum tension T, so we get the minimum acceleration. So the person must descend with more acceleration than this.

a = g - 50 * g / 98 = 4.8 m/sec² if g = 9.8 m/s²