Answers

2015-10-01T13:27:51+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Write LHS in terms of sine and cos.
LHS
   = sin² / [cos (sin+cos)]  +  cos² / [sine (cos - sine)]
   = [ Sin³ (cos - sine) + Cos³ (sin + cos) ] / [sine cos (cos² - sin²)]
   = [ Sin cos (cos²+sin²) - (cos² - sin²)(cos²+sin²) ] / [sine cos (cos2 ) ]
   = [ sin cos - cos2 ] / [sine cos cos2]
   = Sec2θ - 2 cosec2θ
this is the answer for LHS.

==========================
the two expressions on the right side are equal.

1+ tan + cot  = 1 + (sin²+ cos²)/(sin cos )  = 1 + cosec  sec.



1 5 1