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AC=42cm AB=20cm BC=34cm USING HERONS FORMULA = √s(s-a)(s-b)(s-c) area of ΔABC 42+20+34/2=48 ⇒√48(48- 42)(48-20)(48-34) ⇒√48*6*28*14 ⇒336 ∵area of ΔABC=336cm now, area of parallelogram ABCD= 336*2=672cm

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Area of the parallelogram=sum of the area of the two triangles, made by any one of the diagonal, right!!! Area of a triangle=1/2*base*height Here, we know all the three sides- 34,20,42. So, we have to use the Heron's formula.

s=semi-perimeter=34+20+42/2 =96/2 =48 cm. Let a=34, b=20; and, c=42. Area of a triangle, =√s(s-a)(s-b)(s-c) =√48(48- 34)(48-20)(48-42) It is because s=48, a=34, b=20, c=42. =√48*14*28*6 =√112896 =336 cm².

Therefore, are of the parallelogram= 2*336 =672 cm².