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2015-10-06T22:35:37+05:30

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Let the velocity at the top of the circle be = V  m/s
let Radius R = 2 meter

The centripetal force on water in the bucket should be more than the gravitational pull.  Then water does not fall.

       m V² / R =  m g      =>    V = √(Rg)  = 2√5  m/sec    as g = 10m/sec 
so velocity of the bucket in the vertical circle must be minimum 2√5 m/s

   then the  period of revolution = T <  2πR/ V = 2.8 sec


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