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2015-10-03T12:13:28+05:30

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Let the numerator of fraction = x
denominator = x+3
fraction is  \frac{x}{x+3}

if 7 is added to the numerator,the fraction increases by unity. Thus

 \frac{x+7}{x+3}= \frac{x}{x+3}+1\\ \\ \Rightarrow   \frac{x+7}{x+3}= \frac{x+x+3}{x+3}\\ \\ \Rightarrow   \frac{x+7}{x+3}= \frac{2x+3}{x+3}\\ \\ \Rightarrow  x+7=2x+3\\ \\ \Rightarrow  x-2x=3-7\\ \\ \Rightarrow  -x=-4\\ \\ \Rightarrow  x=4

Fraction is  \frac{x}{x+3}= \frac{4}{4+3}=\boxed{ \frac{4}{7} }

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2015-10-03T12:19:26+05:30

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I think 4/7 is the answer...The numerator is x so denominator is x+3
So after adding 7 it will be
x+7/x+3=x/x+3+1
x+7/x+3=x+x+3/x+3
x+7/x+3=2x+3/x+3
Since denominators are same. The numerators can be easily compared...
x+7=2x+3
x-2x=3-7
x=4

So Numerator is 4 and denominator is 7
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