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If its cube...use the identity of acube + bcube...it may help
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u need to put the solution, not the methof.
i was akin if it was cube or 3?
if its 3 then u r wrong!!
Cos(x) appears thrice, and so does sin(x).

sin(3x)cos(x)cos(x)cos(x)+cos(3x)sin(x)sin(x)sin(x) \\ sin(3x)(cos(x))^3+cos(3x)+(sin(x))^3 \\ (sin3x+cos3x)(cosx+sinx)^3

Ans= (sin3x+cos3x)(cosx+sinx)^3
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