Answers

2014-06-22T14:03:48+05:30
Let three number are a,b,c 
a+b+c = 11 --------------(1)
1/a + 1/b + 1/c = 1 --------(2)
a,b,c are in H.P. then 1/a,1/b,1/c are in A.P.
1/a + 1/c = 2/b
put in equation (2)
1/b + 2/b = 1
3/b = 1
b = 3
a+c = 8  ----------------(3)
1/a + 1/c = 2/3
(a+c)/ac = 2/3
ac = 12
(a-c)² = (a+c)² - 4ac
         = 64 - 48
         = 16
a-c = 4  ---------------(4)
(3) + (4)
2a = 12
a = 6
c = 2


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