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I have a box. The top's area is 240 square inches, the front's area is 300 square inches and the end's area is 180 square inches. What are the dimensions

of the box?


The dimensions of the box are:-Length=20, depth=12, height=15.

This is easily solved with a little simple algebra. If we call the three sides A, B, and C we have:

A x B = 240
A x C = 300
B x C = 180

Multiplying these together we get:

   (A x B) x (A x C) x (B x C) = 240 x 300 x 180

   A2 x B2 x C2 = 12,960,000

   (A x B x C)2 = 12,960,000

Which means that:

   A x B x C = 3600

Substituting A x B = 240 back in gives C = 15 and the rest follow. 
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