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If a, b, c are in ap then 2b=a+c
if a , mb , c  are in gp  then m²b²=ac
using these relation you can get the ans

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A,b,c are in A.P hence 2b = a+c  -------------(1)
a,mb,c are in G.P. hence m²b² = ac  ---------------(2)
(2) ÷ (1)
2/m²b = ac/(a+c)
2/m²b = 1/a + 1/c
hence a,m²b,c are in H.P.
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