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Find the value of p so the quadratic equation has equal root

quadratic equation is (p-12)x²-2(p-12)x+2=0 urgent pleseeeeeee ans fast.


When -bx-b-4ac=0,they have equal root so,
so,  -2(p-12)x-2(p-12) -4x2x(p-12)=0
=       -2p-24x-2p-24 -8p+96=0
=        4p+624-8p+96=0
=        -4p+720=0
=       -4p= -720
=        p=  -720/-4
=        p=180
value of p=  180
                              hope its correct

2 5 2
nice but I not copied
ans of this Q is not available on the internet
thank you
ur wlcm
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