Answers

2015-10-18T12:33:45+05:30
we know that kinetic energy=1/2 mv^2.
∴if the momentum is doubled then,
K.E=1/2.m.v^2
K.E=1/2.2m.(2v)^2
K.E= 4mv^2.
kinetic energy will be four times.
           i hope that this will help u......................

0