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From point A which is at distance of 10 cm from the center O of a circle of radius 6 cm, the pair of tangents AB and AC to the circle are drawn. What will

be the area of quadrilateral?


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Length of each tangent = √(10² - 6²) = 8 cm
Area  of triangles OAB = triangle OAC =  1/2 * 8 * 6 = 24 cm²

area of quadrilateral OBAC = 2 * 24 = 48 cm²

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