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(Ac)2=(25-bc) 2 Using pythagorus th Ac2=ab2+bc2 Using value of ac n ab Bc =12cm Therefore ac =13 cm Sin a =12/13 Cos a=5/ 13 Sec c=13/ 12
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AC=13 and BC=12 therefore SinA=12/13  CosA=5/13 and SecA=13/5
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