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Height of a tree is 10m .It is bent by the wind in such a way that its top touches the ground and makes an angle of 60°with the ground .at what height from

The total height of tree is 10 m Then one part is x m And, the other part will be (10-x) The broken part forms the hypotenuse and the part firmed to the ground is the perpendicular. sin60°=p/h √3/2=x/10-x 10√3-√3x=2x (10*1.73)-1.73x=2x 17.3=2x+1.73x 17.3=3.73x 1730/373=x 4.68=x

Let the tree be AB with its top A so AB=10 m now it bents and touch the ground so let that point be C making angle 90 with ground now it became a triangle ABC in triangle ABC angle B=60 now sin 60 = √3/2 also sin 60 =opp/Hypo ⇒√3/2=opp / 10 ⇒opp=5√3