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Height of a tree is 10m .It is bent by the wind in such a way that its top touches the ground and makes an angle of 60°with the ground .at what height from

the bottom did the tree get bent


The total height of tree is 10 m
Then one part is x m
And, the other part will be (10-x)
The broken part forms the hypotenuse and the part firmed to the ground is the perpendicular.

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Let the tree be AB with its top A so 
AB=10 m
now it bents and touch the ground so let that point be C   making angle 90 with ground
now it became a triangle ABC
in triangle ABC  angle B=60
now sin 60 = √3/2
also sin 60 =opp/Hypo
 ⇒√3/2=opp / 10

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