# From a waterfall , water is pouring down at rate of 100 kg per sec if the height is 100m the power delivered is

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Mass pouring = 100 kg/s

height = 100m

Maximum energy that can be delivered per second = mgh

⇒ Max. Power = 100kg/s × 9.8 m/s² × 100m

⇒ Max. Power = 98000 J/s

⇒ Max. Power = 98 kJ/s = 98 kW

But all the energy is not transferred from water. The water which fell still has some Kinetic energy. We normally take 50% efficiency. So 50% of maximum Power is delivered.

So power delivered = 98 × (50/100) = 49 kW

height = 100m

Maximum energy that can be delivered per second = mgh

⇒ Max. Power = 100kg/s × 9.8 m/s² × 100m

⇒ Max. Power = 98000 J/s

⇒ Max. Power = 98 kJ/s = 98 kW

But all the energy is not transferred from water. The water which fell still has some Kinetic energy. We normally take 50% efficiency. So 50% of maximum Power is delivered.

So power delivered = 98 × (50/100) = 49 kW