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A piece of material of mass 100g is immersed in a measuring cylinder having water at a mark of 30ml. The water level rises to 38ml. Calculate the loss of

weight of the piece of material.and also the buoyant force experienced by the piece of material.
thanks a lot for answering this too..................
You are welcome!
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Initial water mark on cylinder = 30ml
final water mark on cylinder = 38ml
volume of water displaced = 38 - 30 = 8ml

8ml = 8cm³
density of water = 1g/cm³
mass of water displaced = density*volume = 1 *8 = 8g = 0.008 kg

loss of weight = weight of water displaced = 0.008*9.8 N =0.0784 N
Loss of weight is same as the buoyant force.
So buoyant force is also 0.0784N
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yeah..seriously!! you can check it..
fine and thanks
see some example with iron ball and wooden object.
The loss of weight will be equal to the buoyant force so the answer is 0.0784N
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