Answers

2015-10-17T23:15:33+05:30
Answer is A.....................

initial acceleration = f
at time t, velocity of lift = ft
at time t, velocity due to gravity = gt
then ball is thrown upward with velocity u, relative to lift
from ground, u = ft+gt
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Please post the solution..or give a hint to solve
@Jahnavi97, Please post the solution..or give a hint to solve
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It's actually wrong..no offense..... I solved it now...vel of body relative to lift is given [u]... acc due to gravity is [-g]...relative acc = [-g-f], since both are in same direction...Time of flight [t] = 2u/[g plus f], took the magnitude of relative acc because time can't be negative.... =>u = t*[g plus f]/2 ==> u = [gt plus ft]/2